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Assume you have a normal distribution with a mean of 56 and a standard deviation of 6. Find the value that gives you a z-score of 1.80. Round your answer to the nearest HUNDREDTH.

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STEP - BY - STEP EXPLANATION

What to find?

The value that gives a z- score of 1.80.

Given:

Mean(μ) = 56

Standard deviation (σ) = 6

x = ?

z = 1.80

Step 1

Recall the formula.


Z=(x-\mu)/(\sigma)

Step 2

Substitute the values into the formula.


1.80=(x-56)/(6)

Step 3

Cross - multiply.


10.8=x-56

Step 3

Add 56 to both-side of the equation.


x=10.8+56
x=66.80

ANSWER

66.80

User Tehbeardedone
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