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ABC is a triangle for which < ABC = 90°, AB= 10cm and BC=15cm, Find Ac? how do I solve this?

User Tonylo
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1 Answer

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The Pythagorean theorem states:


c^2=a^2+b^2

where a and b are the legs and c is the hypotenuse of a right triangle.

Applying this theorem to triangle ABC (see the above diagram):


AC^2=AB^2+BC^2

Substituting with AB = 10 cm, BC = 15 cm, and solving for AC:


\begin{gathered} AC^2=10^2+15^2 \\ AC^2=100+225 \\ AC^2=325 \\ AC=\sqrt[]{325} \\ AC\approx18\operatorname{cm} \end{gathered}

ABC is a triangle for which < ABC = 90°, AB= 10cm and BC=15cm, Find Ac? how do-example-1
User CRAFTY DBA
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