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The sumlog (3)+log (8) ccan also be expressed as+

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The sum of two log functions with the same basis can be expressed as follows:


\log _ax+\log _ay=\log _a(x\cdot y)

In this case, we have a = 5, x = 3, and y = 8. Therefore:


\log _53+\log _58=\log _5(3\cdot8)=\log _524

So, option C is correct.

User Ayaz Alifov
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