The probability of selecting a student who is a man or a non-smoker, accounting for the fact that 135 men are non-smokers, is approximately 0.910.
How do we find the probability of getting a man and non-smoker?
There are 399 students in total.
57 students are regular smokers.
20 students are heavy smokers.
176 students are men.
322 students are non-smokers.
P(Regular or Heavy Smoker) = (Regular Smokers + Heavy Smokers)/Total Students
P(Regular or Heavy Smoker) = (57+20)/399 = 0.193
P(Man or Non-Smoker) = P(Man) + P(Non-Smoker)−P(Man and Non-Smoker)
176/399 + 322/399 - 135/399
P(Man or Non-Smoker) = 0.441 + 0.807 - 0.338
P(Man or Non-Smoker) = 0.91