Part a)
Since m is the number of miles driven and company A charges a base price of $56 plus a charge of $0.25 per mile, we can write the following equation:
![Ca=56+0.25m](https://img.qammunity.org/2023/formulas/mathematics/college/iqnvatdig6ewei70r42j51jr6a2bo1bgav.png)
Part b)
Again, since m is the number of miles driven and company B charges a base price of $45 plus a charge of $0.58 per mile, we can write the following equation:
![Cb=45+0.58m](https://img.qammunity.org/2023/formulas/mathematics/college/my16gopt47vodtbcp0liwua1agfgs1vp6b.png)
Part c)
The cost of renting a car from both companies will be the same when:
![Ca=Cb](https://img.qammunity.org/2023/formulas/mathematics/college/ewv0bdqjnnj0rqs1p85ldf5bnfjfdhwbn9.png)
Then, we solve the following equation for m:
![\begin{gathered} 56+0.25m=45+0.58m \\ \text{ Subtract 56 from both sides of the equation} \\ 56+0.25m-56=45+0.58m-56 \\ 0.25m=0.58m-10 \\ \text{ Subtract 0.58 m from both sides of the equation} \\ 0.25m-0.58m=0.58m-10-0.58m \\ -0.33m=-10 \\ \text{ Divide by 0.33 from both sides of the equation} \\ (-0.33m)/(-0.33)=(-10)/(-0.33) \\ m\approx33.33\Rightarrow\text{ The symbol }\approx\text{ is read](https://img.qammunity.org/2023/formulas/mathematics/college/lb78ff0s3fp2nn27uyj64i1z96b3gtbke7.png)
Therefore, the cost of renting a car from both companies will be the same at 33.33 miles.