Question

Solve the system by substitution.3x+4y=50 -2x=y

Answer 1

we have the following:

`\begin{gathered} 3x+4y=50 \\ -2x=y \end{gathered}`

replacing:

`\begin{gathered} 3x+4\cdot-2x=50 \\ 3x-8x=50 \\ -5x=50 \\ x=-(50)/(5) \\ x=-10 \end{gathered}`

now, from y:

`\begin{gathered} y=-2\cdot-10 \\ y=20 \end{gathered}`

Therefore:

x = -10

y = 20