hello, to solve this question, we need to look the function:
![y\text{ }\ge\text{ }(1)/(3)x\text{ +2}](https://img.qammunity.org/2023/formulas/mathematics/college/h00vblyyvieratrzjutx700zg961nwojeb.png)
So, let's see the graphics:
remember: for this question, only values equal to or greater than y are of interest
We can solve by attempts:
when x = 0:
![\begin{gathered} y\text{ }\ge\text{ }(1)/(3)\cdot0\text{+2} \\ y\ge2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yz3ylc6ty0eip9ous0w22ow93dp70ze5ps.png)
At this moment, we can discard two options: A and C.
Why? Because when x = 0, just interest for us y>= 2.
when x = 1:
![\begin{gathered} y\text{ }\ge\text{ }(1)/(3)\cdot1\text{+2} \\ y\text{ }\ge2.33 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7fk2zdhl4zjg196phmrgd1j5lj7cmnauci.png)
when x = 2:
![\begin{gathered} y\text{ }\ge\text{ }(1)/(3)\cdot2\text{+2} \\ y\ge2.66 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fbnpogutw193r2lffphu1vg89swf7ll263.png)
As we have the sign "greater than or equal to", we can conclude that it is a closed representation, so the line must be continuous.
Right answer: B.