Given
The function is given as

Required
To determine the amplitude and period.
Step-by-step explanation
The general trigonometric equation is

where A is the amplitude.
Compare with the given equaiton.
A =3.
Then the amplitude is 3.
Now , find the period.

Substitute the value of B in the expression.

Answer
Hence the amplitude is 3 and period is

The graph of the equation is determined as