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What is the value of (x^2 + (2y)) ÷ ((2w) + 3z) for w = 2, x = 5, y = 8, and z = 3?

User Oknoorap
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1 Answer

1 vote

Answer:

For w = 2, x = 5, y = 8, and z = 3,


(x^2+2y)/(2w+3z)=(41)/(13)

Step-by-step explanation:

Given the expression:


(x^2+2y)/(2w+3z)

for w = 2, x = 5, y = 8, and z = 3, we have:


\begin{gathered} (5^2+2(8))/(2(2)+3(3)) \\ \\ =(25+16)/(4+9) \\ \\ =(41)/(13) \end{gathered}

User Thomas Collett
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