Question

I already graphed the first question, need number 2 please

Answer 1

For the equation y = 2x + 3, calculate the x and y intercepts

when y = 0

0 = 2x + 3

x = -3/2

x = -1.5

The x-intercept = (-1.5, 0)

when x = 0

y = 2(0) + 3

y = 3

The y-intercept = (0, 3)

Locate the points (-1.5, 0) and (0, 3) to graph the equation y = 2x + 3

For the equation y = -1/3 x + 2, calculate the x and y intercepts

when y = 0

`\begin{gathered} 0=-(1)/(3)x+2 \\ (1)/(3)x=2 \\ x=6 \end{gathered}`

The x-intercept = (6, 0)

when x = 0

y = -1/3 (0) + 2

y = 2

The y-intercept = (0, 2)

The graphs of the two equations are plotted using their x and y intercepts as shown below

y = 2x + 3 is plotted in red

y = -1/3 x + 2 is plotted in blue

The solution to the system of equations represented by the two lines is (-0.429, 2.143)