Question

A. O 33.836 kg m/sB. O31.903 kg m/sC. O 12.883 kg m/sD. O 19.2 kg m/sE. O 23.979 kg m/s6. An object of mass 9.5 kg was acted by a force of 14.2 N for3.6 seconds. If its initial speed was 4.0 m/s,calculate its final speed. (1 point)A) 14.189B) 16.584C) 2.015D)3.015E) 9.381

Answer 1

Given:

The mass of the object is m = 9.5 kg

The force acting on it is F = 14.2 N

The time duration is t = 3.6 s

The initial speed is

`v_i=\text{ 4 m/s}`

To calculate the final speed.

Step-by-step explanation:

An impulse of an object is calculated as

`Impulse\text{ = F}* t`

It can also be written as

`\begin{gathered} Impulse\text{ = change in momentum} \\ =mv_f-mv_i \end{gathered}`

So, the final velocity can be calculated by equating both the formula

`\begin{gathered} F* t=mv_f-mv_i \\ mv_f=F* t+mv_i \\ v_f=((F* t)+mv_i)/(m) \end{gathered}`

On substituting the values, the final speed will be

`\begin{gathered} v_f=((14.2*3.6)+(9.5*4))/(9.5) \\ =9.381\text{ m/s} \end{gathered}`

Thus, the correct choice is E