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What is the simplest radical form of v32
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What is the simplest radical form of v32

User Kevin Doherty
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1 Answer

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We have the following:


\sqrt[]{32}=\sqrt[]{2^5}=\sqrt[]{2^4\cdot2}=\sqrt[]{2^4}\cdot\sqrt[]{2}=2^2\sqrt[]{2}=4\sqrt[]{2}

Therefore, the answer is the option C

User Tahmid Bin Rashid
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