Question

darin wrote 1 1/2 as the sum of three fractions. none of the fractions had a denominator of 2 what fractions might darin have used A 1/8+2/8+2/4 B2/8+3/8+5/8 C2/4+2/4+2/4 D3/4+2/4+2/4

Answer 1

`1\text{ }(1)/(2)\text{ }`

Step 1: To find the expression wherein the above can be a sum of three fractions, lets first convert to improper fraction

`\begin{gathered} 1(1)/(2)\text{ =}1+(1)/(2) \\ =(1)/(1)+(1)/(2)=(2+1)/(2) \\ =(3)/(2) \end{gathered}`

Step 2: Check the options given

Then, let's check option A

`(1)/(8)\text{ + }(2)/(8)\text{ +}(2)/(4)\text{ = }(1)/(8)\text{ + }(2)/(8)\text{ +}(4)/(8)\text{ =}(7)/(8)`

Option A is wrong

Let's try option B

`(2)/(8)\text{ +}(3)/(8)\text{ + }(5)/(8)\text{ = }(10)/(8)\text{ =}(5)/(4)`

Option B is wrong

Let's try option C

`(2)/(4)\text{ +}(2)/(4)+(2)/(4)\text{ =}(6)/(4)\text{ =}(3)/(2)`

Option C is correct

lets also check for option D

`(3)/(4)\text{ +}(2)/(4)+(2)/(4)=(7)/(4)`

Option D is wrong

The answer is option C