Question

An airplane starts at rest and accelerates at 5.7 m/s^2 at an angle of 31 south of west after 9 s, how far in the westerly direction has the plane traveled?

Answer 1

`\begin{gathered} acceleration=a=5.7m/s^2 \\ V_o=0\text{ m/s} \\ x_o=\text{ 0 m} \\ t=9\text{ s} \\ x_f=? \\ x_f=x_o+V_ot+(at^2)/(2) \\ x_f=\text{0 m}+(0\text{ m/s})(9s)+((5.7m/s^2)(9s)^2)/(2) \\ x_f=\text{ }((5.7m/s^2)(9s)^2)/(2) \\ x_f=230.85\text{ m} \\ In\text{ the westerly }direction \\ \theta=31 \\ x_f=230.85\text{ m }\cos (31) \\ x_f=197.87\text{ m} \\ \text{After 9 seconds }the\text{ airplane has traveled 197.87 m in the westerly direction} \end{gathered}`