Question

Answer the following question .

Answer 1

If two lines are perpendicular, then:

`m1* m2=-1`

From the equation:

`y=-(1)/(3)x-5`

We can conclude:

`m1=-(1)/(3)`

So:

`\begin{gathered} -(1)/(3)* m2=-1 \\ m2=3 \end{gathered}`

Let:

`(x1,y1)=(0,-3)`

Using the point-slope equation:

`\begin{gathered} y-y1=m2(x-x1) \\ y-(-3)=3(x-0) \\ y+3=3x \\ solve_{\text{ }}for_{\text{ }}y\colon \\ y=3x-3 \end{gathered}`