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Find the perimeter of a rectangle that has an area of 14c2 − c − 4 and its width is 2c + 1.

User BrianKE
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1 Answer

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You have a rectangle with the following expressions for the area and the width:

Area: A = 14c² - c - 4

width: w = 2c + 1

Take into accoint that the area of a rectangle is the product between its width and length.

A = w·l

if you divide the area over the width you obtain the length:

l = A/w

then, divide the expressions for A and w, in standard division form, as follow:

14c² - c - 4 | 2c + 1

-14c²-7c 7c - 4

-8c - 4

8c +4

0

then, the result is 7c - 4, which is the expression for the length of the rectangle:

length: l = 7c - 4

Now, consider that the perimeter of the rectangle is given by:

P = 2w + 2l

replace the expressions for w and l:

P = (2c + 1) + (7c - 4) open parenthesis

P = 2c + 7c +1 - 4

P = 9c - 3

Hence, the permeter

User Alex Fire
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