The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.
The explicit formular for the geometric sequence is shown as;
![\begin{gathered} ar^(n-1) \\ \text{Where a is the first term in the sequence,} \\ r\text{ is the common ratio betw}een\text{ every successive term} \\ \text{And n is the nth term} \\ \text{The explicit formular for the height of the ball on the 10th bounce is;} \\ ar^(n-1) \\ 54*(0.750)^(10-1) \\ 54*(0.750)^9 \\ 54*0.07508468\ldots \\ 4.0545 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qt70yearwc4h62wancqh733a714edllimq.png)
The explicit formula is shown as;
54 x (0.750)^9
The rest is simply to solve for the height on the 10th bounce