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Part II Dilution Problems: 20. A bottle is labeled 12,0 M HCI. What volume of the original HCl is required to make 20.0 mL of 3.0 M HCl solution?

1 Answer

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Answer:


5.0\text{ mL}

Step-by-step explanation:

Here, we want to get the volume needed to make 20 mL of 3 M HCl

Mathematically, according to the dilution formula:


C_1V_1\text{ = C}_2V_2

Where C1, V1 are the initial molarity and volume respectively, while:

C2, V2 are the final molarity and volume respectively

Substituting the values, we have it that:


\begin{gathered} 12\text{ }*\text{ V}_1\text{ = 20 }*\text{ 3} \\ V_1\text{ = }(20*3)/(12) \\ V_1\text{ = 5 mL} \end{gathered}

User Lew Winczynski
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