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28 votes
28 votes
1. If 3.2 L of nitrogen monoxide and 4.3 g of oxygen gas are combined, what volume of nitrogen dioxide will be formed? 2NO + 0, -> 2NO,​

User Udani
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1 Answer

9 votes
9 votes

Answer:


3.2 / 22.4 = (1)/(7) mol \: no


4.3 / 32 = 0.134mol \: o2

Step-by-step explanation:

NO is limit reactant so:

1÷7×46=6.57 grams of NO2 will form

User SpoBo
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