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A 30.0 kg bike accelerates at 7.0 m/s2. How much force is applied to the bike?

User Mrjf
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1 Answer

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According to Newton's Second Law of Motion, the net force F that acts on an object with mass m that accelerates at a rate a is:


F=ma

Substitute m=30.0kg and a=7.0m/s^2 to find the net force on the bike:


\begin{gathered} F=(30.0\operatorname{kg})(7.0(m)/(s^2)) \\ =210N \end{gathered}

Then, the net force applied to the bike, is 210 N.

User Athos
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