Question

I just want to know if I solved it right before I turn it in

Answer 1

Solving for x in the second equation, we get:

`\begin{gathered} -3x+4y=-13 \\ -3x=-13-4y \\ x=(-13)/(-3)-(4y)/((-3)) \\ x=(13)/(3)+(4y)/(3) \end{gathered}`

Replacing x on the first one and solving for y, we get:

`\begin{gathered} 2x+5y=1 \\ 2((13)/(3)+(4y)/(3))+5y=1 \\ (26)/(3)+(8y)/(3)+5y=1 \\ (8y)/(3)+5y=1-(26)/(3) \\ (23)/(3)y=(-23)/(3) \\ y=-1 \end{gathered}`

Finally, replacing y by -1, we get:

`\begin{gathered} x=(13)/(3)+(4)/(3)\cdot(-1) \\ x=(13)/(3)-(4)/(3) \\ x=3 \end{gathered}`

Answer: x = 3 and y = -1