Answer:
y=-(2/5)x+2
Explanation:
Given the equation of the line:
![2x+5y-10=0](https://img.qammunity.org/2023/formulas/mathematics/college/sfw6vv5vxywqmet8bpurqt94lyxwwchac0.png)
The slope-intercept form of a line is given as y=mx+b.
Thus, make y the subject of the given equation.
![\begin{gathered} 5y=-2x+10 \\ \text{Divide all through by 5} \\ y=-(2)/(5)x+(10)/(5) \\ y=-(2)/(5)x+2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7rsdp0sgdp17eaby8sarnlz22gwm0hgh1q.png)
The slope-intercept form of the equation is y=-(2/5)x+2.
Next, the lines are graphed using the intercepts.
When y=0
![\begin{gathered} 0=-(2)/(5)x+2\implies(2)/(5)x=2 \\ \text{Multiply both sides by }(5)/(2) \\ (2)/(5)*(5)/(2)x=2*(5)/(2) \\ x=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mtinbkw4tnvgh44my7hb9i689uc30walv1.png)
• The x-intercept is (5,0)
,
• From the slope-intercept form, the y-intercept is (0,2).
Join the two points using a straight line as shown below: