We are asked to find the equation of the line that has the same slope as the equation below
![6x+3y=12](https://img.qammunity.org/2023/formulas/mathematics/college/41fzwro07c2k5221rrqrtpz5c355tsv6ep.png)
And it passes through the point (2, 1)
Let us first re-write the given equation into the slope-intercept form.
To do that, simply separate out the y variable.
![\begin{gathered} 6x+3y=12 \\ 3y=-6x+12 \\ y=-(6x)/(3)+(12)/(3) \\ y=-2x+4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ajy3khb6b2uou0io772g9jadg07ypeos49.png)
The standard slope-intercept form is given by
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where m is the slope and b is the y-intercept.
Comparing the standard form with the above equation we see that
Slope = m = -2
So, the equation of the line that we want to find out becomes
![y=-2x+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/rlu6nfc7816wamuzwxl9pfle23oh7bwf7c.png)
Now we need to find out the value of y-intercept (b)
Since it is given that the line passes through the point (2, 1) so we can substitute it into the above equation and solve for b.
![\begin{gathered} y=-2x+b \\ 1=-2(2)+b \\ 1=-4+b \\ 1+4=b \\ 5=b \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/brlcivsbmtwn44ind2bumrcxy7qi9jlksd.png)
So, the value of the y-intercept is 5
Therefore, the equation of the line is
![y=-2x+5](https://img.qammunity.org/2023/formulas/mathematics/high-school/mu4o6jzbtomonljpd3dhkx7olgciqacik9.png)