Step-by-step explanation:
According to the next equation,
2Li + Cl₂ → 2 LiCl (completed and balanced)
-------
The oxidation state of each element changes as follows:
Li) goes from 0 to +1
![2Li^0=>\text{ Li}^(+1)+\text{ 2e}^(-1)](https://img.qammunity.org/2023/formulas/chemistry/college/r5nexl1ndebxzgj194t2q8mrxzry0gjrbk.png)
Cl) goes from 0 to -1
![2Cl^0+2e^(-1)=>2Cl^(-1)](https://img.qammunity.org/2023/formulas/chemistry/college/r7owhhho4yvj0qpzxurx9rib5rz4zjltw5.png)
(these equations above are the half-reactions)
Therefore,
Answer:
Lithium undergo oxidation
Chlorine undergo reduction