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Find sn of the arithmetic seriesa1=22 d=-8 n=12

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Given: An arithmetic series with:


\begin{gathered} a_1=22 \\ d=-8 \\ n=12 \end{gathered}

Required: To find the sum of n terms of the given series.

Explanation: The formula for the sum of n terms of an AP is:


S_n=(n)/(2)[2a_1+(n-1)d]

Substituting the values in the above formula gives:


S_n=(12)/(2)[2*22+(12-1)\cdot(-8)]

Solving the above equation-


\begin{gathered} S_n=6(44-88) \\ S_n=-264 \end{gathered}

Final Answer: The sum of the arithmetic series is -264.

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