Question

The instructions are in the photo. Here is the question:f(x)=2(x-3)^2 +1

Answer 1

Given:

`f(x)=2(x-3)^2+1`

Find-: Coordinates of the axis.

Sol:

General equation of the parabola in vertex form.

`\begin{gathered} y=a(x-h)^2+k \\ \\ \text{ Vertex = }(h,k) \end{gathered}`

Compare with genera equation then:

`\begin{gathered} y=a(x-h)^2+k \\ \\ f(x)=2(x-3)^2+1 \\ \\ \text{ So,} \\ \\ h=3 \\ \\ k=1 \end{gathered}`

So the vertex is:

`(h,k)=(3,1)`