We need to write an equation relating x (leg CD) to the given data.
The image shows the right triangle ACD, with legs, in ft, given by:

Also, angle DAC is 25.4ยบ. Since CD is the opposite leg, and AC is the adjacent leg to this angle, we have:

Thus, option A is correct.
Also, we can multiply both sides of the above equation by 1600, to find the equivalent equation:

Thus, option C is also correct.
Notice that:

Therefore, only options A and C are correct.