Question

Please help and show your work!!
Factor the following

`3x^(2) -4x-7`

Answer 1

Explanation:

1.) Use the sum-pruduct pattern

3x^2-4x-7

3x^2+3x-7x -7

Common factor from two pairs

3x^2 +3x-7x-7

3x(x+1) - 7(x+1

Rewrite in factored form

3x(x+1) - 7(x+1)

(3x-7) (x+1)

Answer:

(3x-7)(x+1) I know we both have the same answer

Answer 2

`\sf \huge \boxed{ \boxed{(3x - 7)(x + 1)}}`

Explanation:

to understand this

you need to know about:

• factoring
• PEMDAS

let's solve:

• 
  `\sf \: rewrite \: - 4x \: as \: 3x - 7 x: \\ \sf {3x}^(2) + 3x - 7x - 7`
• 
  `\sf factor \: out \: 3x: \\ \sf3x( x + 1) - 7x - 7`
• 
  `\sf factor \: out \: - 7: \\ \sf3x( x + 1) - 7(x + 1)`
• 
  `\sf \: group : \\ (3x - 7)(x + 1)`

and we are done!