Question

The fertiliser coverage 3/4 in 1/6 hour the unit rate is blank square feet per hour

Answer 1

`\begin{gathered} IN\text{ }(3)/(4)\text{ OF SQUARE FEET IN }(1)/(6)\text{ hours, WE HAVE THE RATE} \\ ((3)/(4))/((1)/(6))=(3\cdot6)/(4\cdot1)=(18)/(4)=(9)/(2) \\ By\text{ converting to mixed number, one has} \\ (9)/(2)\Rightarrow4(1)/(2) \end{gathered}`