Question

How far will a rock starting from rest fall freely in 6.00 seconds

Answer 1

Given data

*The initial speed of the rock is u = 0 m/s

*The given time is t = 6.00 s

*The value of the acceleration due to gravity is g = -9.8 m/s^2

The formula for the distance traveled by the rock is given by the equation of motion as

`d=ut+(1)/(2)gt^2`

Substitute the known values in the above expression as

`\begin{gathered} d=(0)(6.0)+(1)/(2)(-9.8)(6.0)^2 \\ =-176.4\text{ m} \\ \approx-176\text{ m} \end{gathered}`