45.4k views
4 votes
-12x+6y=-12 graph Please help with equation

1 Answer

0 votes

In ths problem, we need to graph a linear equation in standard form: ax + by = c

The easiest way to do this is to use the x-intercept and y-intercept:

- x-intercept, where the graph crosses the x-axis when y = 0

- y-intercept, where the graph crosses the y-axis when x = 0

We are given the equation


-12x+6y=-12

To find the x-intercept, we will let y = 0, then solve for x. So,


\begin{gathered} -12x+6(0)=-12 \\ -12x=-12 \end{gathered}

Divide by -12 on both sides:


\begin{gathered} (-12)/(-12)x=(-12)/(-12) \\ \\ x=1 \end{gathered}

The x-intercept is at x = 1, so the point we can graph is (1,0):

Next, we can find the y-intercept by letting x = 0. That gives us:


\begin{gathered} -12(0)+6y=-12 \\ \\ 6y=-12 \end{gathered}

Divide both sides by 6:


\begin{gathered} (6y)/(6)=-(12)/(6) \\ \\ y=-2 \end{gathered}

So the y-intercept is y = -2 at the point (0,-2). We can graph that point next:

Finally, we can u

-12x+6y=-12 graph Please help with equation-example-1
-12x+6y=-12 graph Please help with equation-example-2
User Boluc Papuccuoglu
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories