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Paul has 5 books to place on a shelf. How many possible arrangements of all 5 books are there?

User Dorian
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Step-by-step explanation

In the question, we are told that paul has 5 books to place on a shelf. This is a case of arrangement which requires also using permutation to solve the question.

We will apply the formula below;


n!=n(n-1)(n-2)(n-3)\ldots\ldots\ldots\text{.}

Thereofore,


n!=5*4*3*2*1=120\text{ways}

Answer:

User Scott Zhu
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