Question

Solve the equation using the quadratic formula. 3y^2 - 6y = 1

Answer 1

we have the equation

3y^2 - 6y = 1

equate to zero

3y^2 - 6y - 1=0

a=3

b=-6

c=-1

substitute the given values in the formula

`y=\frac{-(-6)\pm\sqrt[]{-6^2-4(3)(-1)}}{2(3)}`
`y=\frac{6\pm\sqrt[]{48}}{6}`

simplify

`y=\frac{6\pm4\sqrt[]{3}}{6}`

the solutions for y are

`y=1+\frac{2\sqrt[]{3}}{3}`

and

`y=1-\frac{2\sqrt[]{3}}{3}`