Question

Given the coordinate plane and points provided highlight the point whose distance from point A is approximately 7.1 units

Answer 1

Point D (-4, -4)

Explanations

In order to determine the point whose distance from point A is approximately 7.1 units, we will use the distance formula expressed as:

`D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`

Given the coordinate points A (1, 1), we need to determine the other coordinate from A that will give a distance of 7.1 units

Using the coordinate point D (-4, -4). The distance AD is calculated as:

`\begin{gathered} AD=\sqrt[]{(1-(-4))^2+(1-(-4))^2} \\ AD=\sqrt[]{(1_{}+4)^2+(1+4)^2} \\ AD=\sqrt[]{5^2+5^2} \\ AD=\sqrt[]{50} \\ AD\approx7.1\text{units} \end{gathered}`

This shows that the point whose distance from point A is approximately 7.1 units is the coordinate point D