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\sqrt[3]{32x {}^(7)y ^(4) }??? help please

User BraggPeaks
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1 Answer

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\sqrt[3]{32x^7y^4}

we will simplify the expression above


\sqrt[3]{(8)\cdot(4)\cdot x^6\cdot x^{}\cdot y\cdot y^3}

then we have


\sqrt[3]{8x^6y^3}\cdot\sqrt[3]{4xy}

The expression simplified is


2x^2y\sqrt[3]{4xy}

User Kacperito
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