Step-by-step explanation:
![f(x)=(3x)/(x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/vkubnv0p430uxwv1b36oztlcl7lti0e0no.png)
To find the domain we have to take a look at every part of the function that contains 'x'. In this function there are two places where x is:
![3x\rightarrow\text{ there's no restriction about the values 'x' can take in this part}](https://img.qammunity.org/2023/formulas/mathematics/college/jmoocjw2zpu3o8xhdm27cgy7pior6b7e0c.png)
![\begin{gathered} (x-1)\rightarrow\text{ since this is in the denominator of the function, it cannot be zero} \\ \text{therefore} \\ x-1\\e0\Rightarrow x\\e1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fgg5act5sufz9xhu9qxno6xcxvrsvqhsuz.png)
Answer:
The domain of the function is all real numbers except 1:
![D\colon x\in(-\infty,1)\cup(1,\infty)](https://img.qammunity.org/2023/formulas/mathematics/college/teaue8rzgomg7mhok7itw5umc7p0kr8dah.png)
Around x = 1, the function goes to infinty. To the left of x = 1 it's negative infinity and to the right it's positive infinity