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Express Y as a function of x. The constant C is a positive number. In y= In 10x + In C

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\ln (y)=\ln (10x)+\ln (C)

Using the property of the addition of logs:


\begin{gathered} \log _z(xy)=\log _z(x)+\log _z(y) \\ so\colon \\ \ln (10x)+\ln (C)=\ln (10x\cdot C)=\ln (10Cx) \end{gathered}
\ln (y)=\ln (10Cx)

Take the exponential function of both sides:


\begin{gathered} e^(\ln (y))=e^(\ln (10Cx)) \\ y=10Cx \end{gathered}

User MattRowbum
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