Question

What is the midpoint of (4,-5) and (10,3)

Answer 1

The formula for the midpoint of the given coordinate is,

`(x,y)=((x_1+x_2)/(2),(y_1+y_2)/(2))`

Now, applying the formula to the given coordinate,

`\begin{gathered} (x,y)=((4+10)/(2),(-5+3)/(2)) \\ (x,y)=((14)/(2),(-2)/(2)) \\ (x,y)=(7,-1) \end{gathered}`

So, the required mid point is (7,-1).