Question

Two blocks are in a contact on a frictionless horizontal surface. The block have masses 2.0 kg and 1.0kg. A horizontal force of 15 n pushes against the 2.0 kg block, which then pushes against. Find the acceleration .Force between two blocks.

Answer 1

We have the next diagram

Then we analyse the equation

`F=ma`

In our case

F=15N

m=2+1=3

a=?

`15=(3)a`

Then we isolate the a

`a=(15)/(3)=5\text{ m/s}^2`

Then for the force between the blocks we already know the acceleration

`a=5\text{ m/s}^2`
`F=1\cdot5=5N`