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Determine the density of a cylindrical solid with a mass of 19.8 g, a diameter of 9.5 mm, and a length of 20.8 mm in g/cm3. Pi = 3.14ROUND ANSWER TO ONE DECIMAL PLACE.

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gDensity is a property of matter that relates the mass to its volume, we can calculate it with the following equation:


\rho=(M)/(V)

Where,


\begin{gathered} \rho\text{ is the density of the substance} \\ M\text{ is the mass of the substance}=19.8g \\ \text{V is the volumen of the substance} \end{gathered}

Now, we have to calculate the volume of the solid. We do that by calculating the volume of a cylinder. The equation is:


V=\pi* r^2* h

Where,

Pi=3.14

r= Radius = Diameter/2 = 9.5mm/2=4.75mm =0.475cm

h = Length = 20.8mm = 2.08cm

We replace the values:


\begin{gathered} V=\pi*(0.475\operatorname{cm})^2*2.08\operatorname{cm} \\ V=1.47\operatorname{cm}^3 \end{gathered}

Now, we replace the known values in the density equation:


\rho=(M)/(V)=\frac{19.8g}{1.47\operatorname{cm}^3}=13.4(g)/(cm^3)

So, the density of a cylindrical solid with a mass of 19.8g is 13.4g

User James Jithin
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