Question

If it takes 221J of work to do this what is the combined mass of the dog and the basket

Answer 1

We are given that 221J of work is required to lift a mass of 4.75 meters. The amount of work is determined by the following equation:

`W=Fd`

Where:

`\begin{gathered} F=\text{ force} \\ d=\text{ distance} \end{gathered}`

The force is equivalent to the combined weight if the dog and the basket multiplied by the acceleration of gravity:

`F=mg`

The distance is the height that the basket is lifted:

`d=h`

Now, we substitute in the equation:

`W=mgh`

Now, we divide by "gh":

`(W)/(gh)=m`

Now, we substitute the values:

`(221J)/((9.8(m)/(s^2))(4.75m))=m`

Solving the operations:

`4.75kg=m`

Therefore, the combined mass is 4.75 kg.