Question

I am having trouble solving this practiceI have attempted this but.. I am not sure if what I did was correct, need more clarificationI believe this is trigonometry

Answer 1

Recall: SOHCAHTOA

Part A

`Cot\text{ G=}\frac{1}{tan\text{ G}}`
`\begin{gathered} tanG=(2√(7))/(6)=(√(7))/(3) \\ \\ Now \\ cot\text{ G=}(1)/((√(7))/(3))=(3)/(√(7)) \end{gathered}`

The final answer

`\begin{gathered} Cot\text{ G=}(3)/(√(7)) \\ \\ rationlise \\ cot\text{ G=}(3*√(7))/(√(7)*√(7))=(3√(7))/(7) \end{gathered}`

Part B

`sin\text{ E=}(6)/(8)=(3)/(4)`

The final answer

`sinE=(3)/(4)`

Part C

`\begin{gathered} sec\text{ G=}\frac{1}{cos\text{ G}} \\ \\ cos\text{ G=}(6)/(8)=(3)/(4) \\ now \\ sec\text{ G=}(1)/((3)/(4))=(4)/(3) \end{gathered}`

Answer summary