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I am having trouble solving this practiceI have attempted this but.. I am not sure if what I did was correct, need more clarificationI believe this is trigonometry

I am having trouble solving this practiceI have attempted this but.. I am not sure-example-1

1 Answer

1 vote

Solution

Recall: SOHCAHTOA

Part A


Cot\text{ G=}\frac{1}{tan\text{ G}}
\begin{gathered} tanG=(2√(7))/(6)=(√(7))/(3) \\ \\ Now \\ cot\text{ G=}(1)/((√(7))/(3))=(3)/(√(7)) \end{gathered}

The final answer


\begin{gathered} Cot\text{ G=}(3)/(√(7)) \\ \\ rationlise \\ cot\text{ G=}(3*√(7))/(√(7)*√(7))=(3√(7))/(7) \end{gathered}

Part B


sin\text{ E=}(6)/(8)=(3)/(4)

The final answer


sinE=(3)/(4)

Part C


\begin{gathered} sec\text{ G=}\frac{1}{cos\text{ G}} \\ \\ cos\text{ G=}(6)/(8)=(3)/(4) \\ now \\ sec\text{ G=}(1)/((3)/(4))=(4)/(3) \end{gathered}

Answer summary

I am having trouble solving this practiceI have attempted this but.. I am not sure-example-1
I am having trouble solving this practiceI have attempted this but.. I am not sure-example-2
User John Dvorak
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