The experiment involves the following reaction:
![\begin{gathered} \text{NaHCO}_3+CH_3COOH\text{ }\rightarrow CH_3\text{COONa}+CO_2+H_2O \\ \text{Baking soda + Vinegar }\rightarrow\text{Sodium acetate}+\text{Carbon dioxide + Water} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/9dvvxwpvhg4q5zm7fcop46wogexv0r2owl.png)
We have that 1 mole of Baking soda reacts with one mol of vinegar to produce one mole of carbon dioxide. Now, let's define what the actual yield is: Moles of the product that we have during the experiment.
Now, we have a relation between the moles and the volume. 1 mol CO2=24 L CO2. If we have the collected volume of CO2=340mL, the moles will be:
![\begin{gathered} \text{MolCO}_2=GivenmLofCO_2*(1molCO_2)/(24LCO_2)*(1L)/(1000mL) \\ \text{MolCO}_2=340mLCO_2*(1molCO_2)/(24LCO_2)*(1L)/(1000mL)=0.014molCO_2 \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/pakrmnggy7shj2eaxx0tmssszz7m521vub.png)
So, the actual yield of carbon dioxide is 0.014mol