Explanations:
According to the given question, we are to plot the graph of the line y= -5(x-5)+1. To do that, we will first create coordinate points on the plane in the form of (x, y)
If y = 10, then;
10 = -5(x-5) + 1
10-1 = -5(x-5)
9 = -5(x - 5)
x- 5 = -9/5
x - 5 = -1.8
x = -1.8 + 5
x = 3.2
Hence one of the coordinates that fit is ABB(3.2, 10)
If y = 5, then;
5 = -5(x-5) + 1
5 - 1 = -5(x - 5)
4 = -5(x - 5)
x - 5 = -4/5
x - 5 = -0.8
x = -0.8 + 5
x = 4.2
Another coordinate point that fit into the plane is B(4.2, 5)
The required graph is as plotted below;