We need to find the mass of 1.6x10^20 molecules of carbon monoxide
First, we must find the number of mol in the 1.6x10^20 molecules
For this, we need to use the avogadro's number ( 6.02*10^23 )
![1.6\cdot10^(20)\cdot\frac{1\text{mol}}{6.02\cdot10^(23)}=2.66\cdot10^(-4)\text{mol}](https://img.qammunity.org/2023/formulas/chemistry/high-school/qc3avd1kdik2l6omia1lldxmr6mn993k4o.png)
Then, we must calculate the molar mass of carbon monoxide
M(CO) = 12 g/mol + 16 g/mol = 28 g/mol
Finally, we must multiply the number of mol by the molar mass to find the mass
![2.66\cdot10^(-4)mol\cdot28(g)/(mol)=7.448\cdot10^(-3)g=0.007448g](https://img.qammunity.org/2023/formulas/chemistry/high-school/uqm06318jb3y0fw76hhkcbung5iw55rxir.png)
ANSWER:
0.007