Question

What is the distance formula between (7,11) and (-1,5)

Answer 1

Let's begin by listing out the information given to us:

`\begin{gathered} (x_(1,)y_1)=(7,11) \\ (x_(2,)y_2)=(-1,5) \end{gathered}`

The distance formula is given by the Pythagoras theorem shown below:

`\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(-1-7)^2+(5-11)^2}=\sqrt[]{(-6)^2+(-6)^2} \\ d=\sqrt[]{36+36}=\sqrt[]{72} \\ d=6\sqrt[]{2} \end{gathered}`

OR

The distance formula is the difference between two points on the same coordinate, all squared

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