Let the perimiter of the square P
Statement 1
The perimeter of the square is greater than 122 inches
This can be expressed in inequality as

Statement 2
The perimeter of the square is less than 134 inches
This can be expressed in inequality as

Since P = 4S, hence

Solving for s gives

Aslo

Hence

Combining the inequalities gives
![30.5<p></p><p></p><p></p>[tex]\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/a7mud9xla9cb7coi5lyyjftkdvudzpri1e.png)