166k views
4 votes
how many moles of iron(lll) hydroxide contain 9.45 x10^25 atoms? Include units and name of atoms/molecule.

User Talemyn
by
4.7k points

1 Answer

3 votes

We are required to calculate the number of moles of iron (III) hydroxide.

We are given the number of atoms = 9.45x10^25.

We also know that 1 mol = 6.022x10^23 atoms

Iron(III) hydroxide moles = 9.45x10^25/6.022x10^23

= 156.925 mol of Iron (III) hydroxide

User Rcapote
by
5.1k points