Answer:
see attached
Explanation:
The boundary lines are drawn by considering the relation as an equation.
The first "equation" describes a line with slope -8/3 through the y-intercept point (0, 6). Another point on that line would be 8 units down and 3 units right of (0, 6), at (3, -2). Both inequalities include the "or equal to" case, so both boundary lines are solid lines.
Since we have y ≥ ( ), the shading is above the line.
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The second "equation" describes a line with a slope of 5/3 through the y-intercept point (0, -7). Another point would be 5 units up and 3 units right of (0, -7), at (3, -2). Since we have y ≤ ( ), the shading is below the line.
That is, the solution region is in the right-hand quadrant of the X where the lines cross. It includes the lines themselves.